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		<title>Mechanics of Materials</title>
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				<category><![CDATA[Mechanical Engineering]]></category>
		<category><![CDATA[A. A]]></category>
		<category><![CDATA[A.It]]></category>
		<category><![CDATA[Bela I. SandorMechanics]]></category>
		<category><![CDATA[dimensional element]]></category>
		<category><![CDATA[element]]></category>
		<category><![CDATA[equilibrium equations]]></category>
		<category><![CDATA[Figure]]></category>
		<category><![CDATA[plane]]></category>
		<category><![CDATA[plane stress]]></category>
		<category><![CDATA[shear]]></category>
		<category><![CDATA[shear stress]]></category>
		<category><![CDATA[shear stresses]]></category>
		<category><![CDATA[stress]]></category>

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		<description><![CDATA[ Bela I. Sandor
Mechanics of materials, also called strength of materials, provides
quantitative methods to determine stresses (the intensity of forces)
and strains (the severity of deformations), or overall deformations or
load-carrying abilities of components and structures. The stress-strain
behavior of materials under a wide range of service conditions must be
considered in many designs. It is also crucial to [...]]]></description>
			<content:encoded><![CDATA[<p><strong><a name="Mechanics"><strong> </strong></a>Bela I. Sandor</strong><br />
<strong>Mechanics of materials</strong>, also called strength of <strong>materials</strong>, provides<br />
quantitative methods to determine<strong> stresses</strong> (the intensity of <strong>forces</strong>)<br />
and strains (the severity of deformations), or overall deformations or<br />
load-carrying abilities of components and structures. The <strong>stress</strong>-strain<br />
behavior of<strong> materials</strong> under a wide range of service conditions must be<br />
considered in many designs. It is also crucial to base the analysis<br />
on correct modeling of component geometries and external loads.<br />
This can be dif?cult in the case of multiaxial loading, and  even more so<br />
if time- or temperature-dependent <strong>material </strong>behaviors must be<br />
considered.</p>
<p>Proper modeling involves <strong>free-body diagrams</strong> and equations<br />
of <strong>equilibrium</strong>. However, it is important to remember that the<br />
<strong>equilibrium</strong> equations of statics are valid only for <strong>forces</strong> or for<br />
<strong>moments</strong> of <strong>forces</strong>, and not for <strong>stresses</strong>.</p>
<h1>Stress</h1>
<p>The intensity of a <strong>force</strong> is called stress and is de?ned as the<br />
<strong>force</strong> acting on an in?nitesimal area. A normal stress ? is de?ned as</p>
<p><img src="/technician_images/20090325114037424.jpg" border="0" alt="" /></p>
<p>where dF is a differential normal <strong>force</strong> acting on a differential area<br />
dA. It is often useful to calculate the average normal stress ? = P/A,<br />
where P is the resultant <strong>force</strong> on an area A. A shear <strong>stress</strong> ? caused<br />
by a shearing <strong>force</strong> V is de?ned likewise,</p>
<p><img src="/technician_images/20090325114121499.jpg" border="0" alt="" /></p>
<p>An average shear <strong>stress</strong> is obtained from V/A.<br />
It is helpful to consider the general cases of <strong>stresses</strong> using rectangular<br />
elements in two and three dimensions, while ignoring the deformations<br />
caused by the <strong>stresses</strong>.</p>
<h1>Plane Stress</h1>
<p>There are relatively simple cases where all <strong>stress vectors</strong> lie in the<br />
same plane. This is represented by a two-dimensional element in<br />
Figure 1.5.1, where ?x and/or ?y may be either tensile (pulling on the<br />
element as shown) or compressive (pushing on the element; not shown).<br />
Normal <strong>stresses</strong> are easy to visualize and set up correctly.</p>
<p><img src="/technician_images/20090325114218649.jpg" border="0" alt="FIGURE 1.5.1 Generalized plane stress." /><br />
<strong>FIGURE 1.5.1 Generalized plane stress.</strong></p>
<p>Shear <strong>stresses</strong> need to be discussed here in a little detail. The notation<br />
means that ?xy, for example, is a shear <strong>stress</strong> acting in the y direction,<br />
on a face that is perpendicular to the x axis. It follows that ?yx is<br />
acting in the x direction, on a face that is perpendicular to the y axis.<br />
The four shear <strong>stress vectors</strong> are pointed as they are because of the<br />
requirement that the element be in <strong>equilibrium</strong>: the net <strong>forces</strong> and<br />
<strong>moments</strong> of <strong>forces</strong> on it must be zero. Thus, reversing the direction<br />
of all four ?s in Figure 1.5.1 is possible, but reversing less than<br />
four is not realistic.</p>
<h1>Three-Dimensional State of Stress</h1>
<p>The concept of <strong>plane stress</strong> can be generalized for a <strong>three-dimensional</strong><br />
element as shown in Figure 1.5.2, working with the three primary faces<br />
of the cube and not showing <strong>stresses</strong> on the hidden faces, for clarity.</p>
<p><img src="/technician_images/20090325114342351.jpg" border="0" alt="FIGURE 1.5.2 Three-dimensional general state of stress." /><br />
<strong>FIGURE 1.5.2 Three-dimensional general state of stress.</strong></p>
<p>Again, the normal <strong>stresses</strong> are easy to set up, while the shear <strong>stresses</strong><br />
may require considerable attention. The complex cases of <strong>stresses</strong><br />
result from multiaxial loading, such as combined axial, bending,<br />
and torsional loading. Note that even in complex situations simpli?cations<br />
are possible. For example, if the right  face in Figure 1.5.2 is a free<br />
surface, ?<sub>x</sub> = ?<sub>xz</sub> = ?<sub>xy</sub> = 0. This leaves a <strong>plane stress</strong> state with<br />
?<sub>y</sub>, ?<sub>z</sub>, and ?<sub>yz</sub>, at most.</p>
<h1>Stress Transformation</h1>
<p>A <strong>free-body</strong> element with known <strong>stresses</strong> on it allows the calculation<br />
of <strong>stresses</strong> in directions other than the given xyz coordinates.<br />
This is useful when potentially critical welded or glued joints, or ?bers<br />
of a composite, are along other axes. The stress transformations are<br />
simplest in the case of plane <strong>stress</strong> and can be done in several ways.<br />
In any case, at a given point in a <strong>material</strong> there is only one state<br />
of <strong>stress </strong>at a particular instant. At the same time, the components<br />
of the <strong>stresses</strong> depend on the orientation of the chosen coordinate<br />
system.</p>
<p>The <strong>stress</strong> transformation equations depend on the chosen coordinate<br />
system and the sign convention adopted. A common arrangement is<br />
shown in Figure 1.5.3, where (a) is the known set of <strong>stresses</strong> and<br />
(b) is the unknown set, denoted by primes.</p>
<p><img src="/technician_images/20090325114621859.jpg" border="0" alt="FIGURE 1.5.3 Elements for stress transformation." /><br />
<strong>FIGURE 1.5.3 Elements for stress transformation.</strong></p>
<p>In the present sign convention an outward normal <strong>stress</strong> is positive,<br />
and an upward shear <strong>stress </strong>on the right-hand face of the element is<br />
positive. The transformation equations are</p>
<p><img src="/technician_images/20090325114713393.jpg" border="0" alt="" /></p>
<p>If a result is negative, it means that the actual direction of the <strong>stress</strong><br />
is opposite to the assumed direction.</p>
<h1>Principal Stresses</h1>
<p>It is often important to determine the maximum and minimum values<br />
of the <strong>stress</strong> at a point and the orientations of the planes of these <strong>stresses</strong>.<br />
For plane <strong>stress</strong>, the maximum and minimum normal <strong>stresses</strong>,<br />
called <strong>principal stresses</strong>, are obtained from</p>
<p><img src="/technician_images/20090325114846880.jpg" border="0" alt="" /></p>
<p>There is no shear <strong>stress</strong> acting on the principal planes on which the<br />
<strong>principal stresses</strong> are acting. However, there are shear <strong>stresses</strong> on<br />
other planes. The maximum shear <strong>stress</strong> is calculated from</p>
<p><img src="/technician_images/20090325114918999.jpg" border="0" alt="" /></p>
<p>This <strong>stress</strong> acts on planes oriented 45? from the planes of<br />
<strong>principal stress</strong>. There is a normal <strong>stress</strong> on<br />
these planes of ?max, the average of ?x and ?y,</p>
<p><img src="/technician_images/20090325114951670.jpg" border="0" alt="" /></p>
<h1>Mohrs Circle for Plane Stress</h1>
<p>The equations for <strong>plane stress</strong> transformation have a graphical<br />
solution, called Mohrs circle, which is convenient to use in engineering<br />
practice, including back-of-the-envelope calculations. Mohrs circle<br />
is plotted on a ?  ? coordinate system as in Figure 1.5.4, with the center C<br />
of the circle always on the ? axis at ?ave = (?x + ?y)/2<br />
and its radius <img src="/technician_images/20090325115055558.jpg" border="0" alt="" /> The positive ? axis is downward<br />
for convenience, to make ? on the element and the corresponding 2?<br />
on the circle agree in sense (both counterclockwise here).<br />
The following aspects of Mohrs circle should be noted:<br />
1. The center C of the circle is always on the ? axis, but it may move<br />
left and right in a dynamic loading situation. This should be considered<br />
in failure prevention.<br />
2. The radius R of the circle is ?max, and it may change, even pulsate,<br />
in dynamic loading. This is also relevant in failure prevention.<br />
3. Working back and forth between the rectangular element and the<br />
circle should be done carefully and consistently. An angle ? on the element<br />
should be represented by 2? in the corresponding circle. If ? is positive<br />
downward for the circle, the sense of rotation is identical in the element<br />
and the circle.</p>
<p><img src="/technician_images/20090325115209891.jpg" border="0" alt="FIGURE 1.5.4 Mohrs circle." /><br />
<strong>FIGURE 1.5.4 Mohrs circle.</strong></p>
<p>4. The <strong>principal stresses</strong> ?1 and ?2 are on the ? axis (? = 0).<br />
5. The planes on which ?1 and ?2 act are oriented at 2?p from the<br />
planes of ?x and ?y (respectively) in the circle and at ?p in the element.<br />
6. The <strong>stresses</strong> on an arbitrary plane can be determined by their ?<br />
and ? coordinates from the circle. These coordinates give magnitudes<br />
and signs of the <strong>stresses</strong>. The physical meaning of +? vs. ?<br />
regarding material response is normally not as distinct as +? vs. ?<br />
(tension vs. compression).<br />
7. To plot the circle, either use the calculated center C coordinate and<br />
the radius R, or directly plot<br />
the <strong>stress</strong> coordinates for two mutually perpendicular planes and draw<br />
the circle through the two points (A and B in Figure 1.5.4) which must<br />
be diametrically opposite on the circle. Special Cases of Mohrs<br />
Circles for <strong>Plane Stress </strong>See Figures 1.5.5 to 1.5.9</p>
<p><img src="/technician_images/20090325115314232.jpg" border="0" alt="FIGURE 1.5.5 Uniaxial tension." /><br />
<strong>FIGURE 1.5.5 Uniaxial tension.</strong></p>
<p><img src="/technician_images/20090325115405608.jpg" border="0" alt="FIGURE 1.5.6 Uniaxial compression." /><br />
<strong>FIGURE 1.5.6 Uniaxial compression.</strong></p>
<p><img src="/technician_images/20090325115454447.jpg" border="0" alt="FIGURE 1.5.7 Biaxial tension: ?x = ?y (and similarly for biaxial compression: ?x = ?y )." /><br />
<strong>FIGURE 1.5.7 Biaxial tension: ?x = ?y<br />
(and similarly for biaxial compression: ?x = ?y ).</strong></p>
<p><img src="/technician_images/20090325115538970.jpg" border="0" alt="FIGURE 1.5.8 Pure shear." /><br />
<strong>FIGURE 1.5.8 Pure shear.</strong></p>
<p><img src="/technician_images/20090325115615681.jpg" border="0" alt="" /><br />
<strong>FIGURE 1.5.9 Biaxial tension-compression: ?x = ?y<br />
(similar to the case of pure shear).</strong><br />
<a href="#Mechanics">Top</a></p>
<p>By : E-book Mechanical_Engineering_Handbook</p>
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